[Anhil8tor]

There is a local radio station here that does a one dollar bill game. The game revolves around the fact that the stations call numbers (973) are in the bills serial number in order.

Given that... how many bills would there be with 973 anywhere in the serial number?

I currently have 5 in my possesion even though I don't listen to that radio station ><

[what?]

There is a local radio station here that does a one dollar bill game. The game revolves around the fact that the stations call numbers (973) are in the bills serial number in order.

Given that... how many bills would there be with 973 anywhere in the serial number?

I currently have 5 in my possesion even though I don't listen to that radio station ><

I don't have any. you win.

[Anhil8tor]

I will need flump or san dog for this one.

[Flumper Barflusterbutt]

Hang on. reading it.

[Flumper Barflusterbutt]

Okay, there are 8 digits in a serial number. Do the 973 have to be sequentially in order.

Example: 84957230 (would that count, since there are other numbers between them).

Example: 84973520 (in this one they are sequential).

[Flumper Barflusterbutt]

If 973 was the last three digits, then you could have:

00000973
00001973
00002973

So, that is 5 digits that go from 0 to 99,999 - so that would be 100,000 possible combinations.

Or you could have:

00009730
00009731
00009732, same thing 100,000 combinations. So, now we have 200,000 combinations.

Then:

00097300
00097301........now we have 300,000 combinations.

00973000.........400,000

09730000.........500,000

97300000.........600,000 combinations.

So, out of the 99,999,999 to 0 = 100,000,000 total combinations 600,000 could have a 973 in sequential order.

Odds of finding one 600,000/100,000,000 = 600/100,000 = 6 / 1,000. So, if you had 1,000 bills, 6 should work.

[Anhil8tor]

If 973 was the last three digits, then you could have:

00000973
00001973
00002973

So, that is 5 digits that go from 0 to 99,999 - so that would be 100,000 possible combinations.

Or you could have:

00009730
00009731
00009732, same thing 100,000 combinations. So, now we have 200,000 combinations.

Then:

00097300
00097301........now we have 300,000 combinations.

00973000.........400,000

09730000.........500,000

97300000.........600,000 combinations.

So, out of the 99,999,999 to 0 = 100,000,000 total combinations 600,000 could have a 973 in sequential order.

Odds of finding one 600,000/100,000,000 = 600/100,000 = 6 / 1,000. So, if you had 1,000 bills, 6 should work.

they have to be in order...

for example: 13973247

Now out of all the bills... how many would be located in this 30 or 40 mile radius?

[Flumper Barflusterbutt]

they have to be in order...

for example: 13973247

Now out of all the bills... how many would be located in this 30 or 40 mile radius?

Well, assuming that all 100 million bills are printed and in circulation and not counting the fact that there are alpha numbers along with those serial numbers that could increase the number of bills.

The land area of the united states is 3,794,083.06 square miles. The land area of a 40 mile radius is

PI * 40^2 = 5026.54 sq miles. So that circle around you is 0.0013248 of the total land area. Applying that ratio to the 100,000,000 bills, you would have 132,483.87 dollar bills in that circle. Of those, 6 out of 1,000 would have the 973 in sequence.

So, 6 * 132.48387 = 795 bills.

There are a lot of assumptions in this though. Primarily, a 40 mile radius around new york city would have way more $1 bills than a 40 mile radius around west texas. But, its a hypothetical question.

[Paddy]

Well, assuming that all 100 million bills are printed and in circulation and not counting the fact that there are alpha numbers along with those serial numbers that could increase the number of bills.

The land area of the united states is 3,794,083.06 square miles. The land area of a 40 mile radius is

PI * 40^2 = 5026.54 sq miles. So that circle around you is 0.0013248 of the total land area. Applying that ratio to the 100,000,000 bills, you would have 132,483.87 dollar bills in that circle. Of those, 6 out of 1,000 would have the 973 in sequence.

So, 6 * 132.48387 = 795 bills.

There are a lot of assumptions in this though. Primarily, a 40 mile radius around new york city would have way more $1 bills than a 40 mile radius around west texas. But, its a hypothetical question.

[BANANA]You're taking this seriously I see.[/BANANA]

[Flumper Barflusterbutt]

[BANANA]You're taking this seriously I see.[/BANANA]

There is only one way to take it

[Flumper Barflusterbutt]

In a 30 mile radius, there should be 447 bills with the right serial number.

[Flumper Barflusterbutt]

In a 10 mile radius, there should be 50 bills.

[Flumper Barflusterbutt]

In a 1 mile radius, there would be a 50:50 chance of finding one bill with that number.

[Paddy]

[BANANA]I have one[/BANANA]

[Flumper Barflusterbutt]

[BANANA]I have one[/BANANA]

[banana]Liar![/banana]

[what?]

[BANANA]You're taking this seriously I see.[/BANANA]

[BANANA]fuck, beat me to it. 8 wins[/BANANA]


flump, post all possible combinations that have 973 in sequential order in them in one post with the little banana tag thingees around it and see if the new code or skin or what the buttfucking ever can handle the strain of all those characters. if this works I'm gonna get foolery out of retirement to post his nic a million times again and really load test this sunovabitch

[Blueeyedwoman]

Troublemaker!

[Anhil8tor]

[BANANA]fuck, beat me to it. 8 wins[/BANANA]


flump, post all possible combinations that have 973 in sequential order in them in one post with the little banana tag thingees around it and see if the new code or skin or what the buttfucking ever can handle the strain of all those characters. if this works I'm gonna get foolery out of retirement to post his nic a million times again and really load test this sunovabitch

how much does forum retirement pay?

[Devious]

[BANANA]what's the deal with these signs? :confused:[/BANANA]