06-21-2005, 09:04 PM
![[Image: plot_d1.gif]](http://www.teacherschoice.com.au/Maths_Library/Calculus/plot_d1.gif)
Consider the function plotted in blue above:
y = 0.5x2 - x - 1.5
Using the rules of calculus, the derived function is:
dy/dx = 2Ã0.5x^2-1 - 1Ãx^1-1 - 0
= x - 1
For any 'x' value, the 'y' value of the derived function equals the gradient of a tangent to the original function at that point.

