08-02-2005, 10:54 PM
/(bb|[^b]{2})/
that is the question.
that is the question.
Shakespear for NType
08-02-2005, 10:55 PM
leucetios Wrote:/(bb|[^b]{2})/
that is the question.
I am not sure that you are ready for the answer.
08-02-2005, 10:57 PM
/(bb|[^b]{2})/ = b^b squared
08-02-2005, 11:01 PM
Bill Wrote:/(bb|[^b]{2})/ = b^b squared
back in the days we were making fun of people who were using the inversed polish notation.
I am a leibniz fan.
08-02-2005, 11:02 PM
its not math, bill :S
08-02-2005, 11:03 PM
Ntype Wrote:back in the days we were making fun of people who were using the inversed polish notation.
I am a leibniz fan.
Alas...poor Ntype...i knew him well....
I don't suffer from insanity; I enjoy every minute of it.
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