[asshat]

Originally posted by leucetios@Sep 23 2004, 10:52 PM
http://motorcyclecity.com/chill.htm

or if you want to do it the old school way

Wind chill = 91.4 - (0.474677 - 0.020425 * W + 0.303107 * SQRT(W)) * (91.4 - T)

[snapback]77623[/snapback]

so at 50 mph = W
40 = T

That would be 9.3287 F = wind chill.

But, this must mean that the wind is chilling the 40 degree temperature by 9 degrees. The resulting temperature "feels" like 31 degrees. Ya think?